What is wrong with Yahoo Beta mail - I keep getting Login error Object expected. I did upgrade to ie7?

It's beta...that's why. All the kinks haven't been worked out.





And IE7 has been giving some programs issues...you might want to go back to original Yahoo until your sure that it's IE7 that is't doing this.


I take classes online and IE7 interfers with the program that we have to use.What is wrong with Yahoo Beta mail - I keep getting Login error Object expected. I did upgrade to ie7?
both yahoo beta and ie7 are badWhat is wrong with Yahoo Beta mail - I keep getting Login error Object expected. I did upgrade to ie7?
Friends on line from Alaska to Florida have been having problems, with there connections as well, they all downloaded the new IE7. Sorry you'll have to go back to the old version if you can, and wait for them to fix the bugs.
I am about to drop IE7 because of those issues, send bug reports and nothing happens. They tried there best to copy Netscape, and tell us that we cannot copy a dvd that we bought. I am using SeaMonkey now for 3 days, no cross platform errors whatsoever, but everything went loopy after IE7 was installed. Of course it will be the only one for windows, one day, but for now, no thanks.
its problematic indeed

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A 10.0g object moving to the right at 20.0 cm/s makes an elastic head on collision with a 15.0g object moving?

in the opposite direction at 30.0 cm/s. Find the velocity of each object after the collision.A 10.0g object moving to the right at 20.0 cm/s makes an elastic head on collision with a 15.0g object moving?
Prior to the collision, the 10.0g object has velocity 20.0 and the 15.0g object has velocity -30.0 . After the collision, the 10.0g object has velocity v1 and the 15.0g object has velocity v2.





Momentum is preserved, so


10(20)+15(-30)=10v1+15v2


-250=10v1+15v2


10v1=-250-15v2


v1=-25-1.5v2


Since the collision is elastic, kinetic energy is preserved, so


5(20)虏+7.5(-30)虏=5(v1)虏+7.5(v2)虏


8750=5(v1)虏+7.5(v2)虏


substituting for v1 we get


8750=5(-25-1.5v2)虏+7.5(v2)虏


8750=5(625+75v2+2.25v2虏)+7.5v2虏


8750=3125+375v2+11.25v2虏+7.5v2虏


0=-5625+375v2+18.75v2虏


using the quadratic formula, we get


v2= (-375 卤 750) / 37.5


which has two solutions: v2=-30 or v2=10


plugging these back into v1=-25-1.5v2 we get


v1=20 or v1=-40 respectively.





Solution #1: v1=20 %26amp; v2=-30 : This solution is impossible because it has the left-hand object moving to the right and the right-hand object moving to the left, as if they had passed right through each other.





Solution #2: v1=-40 and v2=10 : This is the correct solution. After the collision, the 10g object is moving 40.0 cm/s to the left and the 15g object is moving 10.0 cm/s to the right.

What is the most memorable sensual feeling you had about an object unrelated to typical sex?

For example, mine was when I was at Magic Mountain where I imagined my vagina engulfing the Goliath ride. Hard to explain, but the weather was scorching and I felt hot and delusional. I was kinda aroused by the thought of the ride's car flying up to the top of me.What is the most memorable sensual feeling you had about an object unrelated to typical sex?
MY DETACHABLE SHOWER HEAD. ENOUGH SAID.What is the most memorable sensual feeling you had about an object unrelated to typical sex?
After drinking several glasses of wine, I felt excited down there.
Ummmm.....sitting on the washer during the spin cycle?? lol
No offense but rofl. i love you
an ***

Is it possible to enter the womb with long penis or object?

you already asked this question. are you a troll?





impossible for a penis. don't flatter yourself.Is it possible to enter the womb with long penis or object?
ha ha unless your penis measures a foot then NO.





Plus the womb is very tight and close, and also protected by the mucus plug, nothing is coming in it.Is it possible to enter the womb with long penis or object?
no not really, the womb is too far up inside a woman.

Do most languages in the world use a structure of subject, object, and then verb?

in KoreanDo most languages in the world use a structure of subject, object, and then verb?
Yes, subject, object, verb [SOV] is the most common. English and the Romance languages are SVO, although most have special cases where other orders are understood (especially in questions or certain tenses).





For example, in English we can say ';With whom did you speak?'; [OSV] or things called locative inversions, where [(O)VS] occurs ';In the garden sat a cat';.





On this also depends the presence or absence of a declension system (synthetic). English has mostly lost its declension although bits remain (whom vs. who, him vs. he). This makes for a generally more rigid word order. Languages like Latin have very strong declension systems. Also, Slavic languages like Polish and Russian retain the system. For example: Latin ';Meam matrem amo ego'; (lit.: My mother love I), ';Amo meam matrem ego'; (lit. Love my mother I), ';Ego amo meam matrem'; (lit: I love my mother), and ';Meam matrem amo (ego)'; (lit. My mother love (I) [the I could and mostly was left out because of the conjugation system of verbs]) are all perfectly understandable, with the last being the most common.





Sorry for writing so much! I just love topics like this so much, so I get carried away. You can e-mail me with ANY questions! I love this grammo-linguistic stuff so much!!!Do most languages in the world use a structure of subject, object, and then verb?
No, the subject/verb/object structure we use in English is the most common.

According to Newton's second law of motion, what does an object with more mass require?

more force to accelerate


more distance to accelerate


less force to accelerate


less speed to accelerate


Whats the correct answer?According to Newton's second law of motion, what does an object with more mass require?
F=ma, so more mass means, more force to accelerate.According to Newton's second law of motion, what does an object with more mass require?
F=ma





If the mass is the same, then the greater the mass, the smaller the acceleration. Therefore, if the mass increases, the force has to increase to give the same acceleration





Actually, you can use daily experiences. For example, you need more force to carry an empty bag than a bag filled with books.





Newton's second law did not deal with distance and speed at all, so discard those two.






the acceleration of an object is proportional to the force applied, and inversely proportional to the mass of the object.





So an object with more mass will require more force to accelerate.
Force = mass *acceleration


So it needs more force to accelerate



force = mass * acceleration ,more acceleration

I need help. How do I find the trajectory of an object?

When I was reading one of my books that talks about physics and it started talking about the trajectory of a cannon that went in an arc shape. I read it a few times, but I couldn't understand it. I want someone to show step by step how to explain how you get the trajectory of an object.I need help. How do I find the trajectory of an object?
The formal for finding the trajectory of an object is as follows:





who+cares= no oneI need help. How do I find the trajectory of an object?
galileo studied projectiles and found that they moved in two directions at the same time. he determined that the motion of a projectile follows the curved path of a parabola. the parabolic path of a projectile is called its trajectory. the shape of a projectiles trajectory depends on its initial velocity-both its initial speed and direction- and on the accleeration due to graity. to understand and analyze projectile motion, you need to consider the horizontal and vertical components of the objects motion seperately.gravity influences he vertical motion of a projectile by acceleratin it downward. note that gravity has no effect on an objects horizontal motion. so the two components of a projectiles motion can be considered independentaly. as a result a projectile experiences both uniform motion and uniformely accelerated motion at the same time.





x direction = d=vt


y direction= d=Vit=1/2at^2

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