An object initially 200 m above the gound is projected upward with an initial speed of 40 m/s at t=0, then fre

e falls to the ground. With what speed and what time will it strike the ground?An object initially 200 m above the gound is projected upward with an initial speed of 40 m/s at t=0, then fre
We can simplify this problem as follows:





Once the object reaches the same point where it was released it will have an speed of 40 m/s downwards.


Now this becomes the initial speed of the object and it has to travel 200m below.





v^2 = u^2 + 2*g*d





v = unknown


u = 40 m/s


g = 9.8 m/s^2


d = 200m





v^2 = 40*40 + 2*9.8*200


v = SQRT(5520)


= 74.29 m/s